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x^2-4x-14400=0
a = 1; b = -4; c = -14400;
Δ = b2-4ac
Δ = -42-4·1·(-14400)
Δ = 57616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{57616}=\sqrt{16*3601}=\sqrt{16}*\sqrt{3601}=4\sqrt{3601}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{3601}}{2*1}=\frac{4-4\sqrt{3601}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{3601}}{2*1}=\frac{4+4\sqrt{3601}}{2} $
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